1.

the hcf and the lcm of two numbers are 9 and 360 respectivily if one number is 45 find another number

Answer»

SOLUTION:

By formula

\mathrm{H} \CDOT \mathrm{C} . \mathrm{F} \times \mathrm{L} . \mathrm{C} . \mathrm{M}H⋅C.F×L.C.M of two numbers = PRODUCT of the two numbers

\mathrm{H} \cdot \mathrm{C} \cdot \mathrm{F} \times \mathrm{L} \cdot \mathrm{C} \cdot \mathrm{M}=9 \times 360H⋅C⋅F×L⋅C⋅M=9×360

Given in question, one of the numbers is 45

Let the ANOTHER number be x

Therefore, substituting the terms in the above formula,

\begin{gathered}\begin{array}{l}{9 \times 360=45 \times x} \\ {x=\frac{9 \times 360}{45}} \\ {x=72}\end{array}\end{gathered}

9×360=45×x

x=

45

9×360

x=72


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