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The half life period of the following first order reaction is (\log 3 = 0.4771) C2H4O2(g) → CH4(g) + CO2(g) Given that initial pressure of C2H4O2(g) is 84 mm and total pressure at the end of 16 minutes is 110 mm (\log 3 = 0.4771)

Answer» The half life period of the following first order reaction is (\log 3 = 0.4771) C2H4O2(g) → CH4(g) + CO2(g) Given that initial pressure of C2H4O2(g) is 84 mm and total pressure at the end of 16 minutes is 110 mm (\log 3 = 0.4771)


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