1.

The half-cell reduction potential of a hudrogen electrode at `pH= 10` will be.A. ` 0. 95 V`B. ` -0. 59 V`C. ` 0.059 V`D. ` -0 .059 `

Answer» Correct Answer - B
`E_(red = E_(cell) ^@ + (0. 0591)/n log [Mn^(=)`
`= 0 + (0.0591)/1 log [10^(-10)]`
` =+ 0.0591 xx - 10 - 0. 59 V`.


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