The `H-O-H` bond angle in the water molecule is `105^@` , the`H -O` bond distance being `0.94 Å`, The dipole moment for the moelcule is `1.85D`. Calculate the charge on the oxygen atom .A. `2 xx 10^(-10)` esuB. `3.28 xx 10^(-10)` esuC. `3.22 xx 10^(-10)` esuD. `1.602 xx 10^(-19)` esu

The `H-O-H` bond angle in the water molecule is `105^@` , the`H -O` bo

1.	The `H-O-H` bond angle in the water molecule is `105^@` , the`H -O` bond distance being `0.94 Å`, The dipole moment for the moelcule is `1.85D`. Calculate the charge on the oxygen atom .A. `2 xx 10^(-10)` esuB. `3.28 xx 10^(-10)` esuC. `3.22 xx 10^(-10)` esuD. `1.602 xx 10^(-19)` esu
Answer» Correct Answer - C

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The `H-O-H` bond angle in the water molecule is `105^@` , the`H -O` bond distance being `0.94 Å`, The dipole moment for the moelcule is `1.85D`. Calculate the charge on the oxygen atom .A. `2 xx 10^(-10)` esuB. `3.28 xx 10^(-10)` esuC. `3.22 xx 10^(-10)` esuD. `1.602 xx 10^(-19)` esu

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