The H.C.F. of two numbers is 23 and their LCM is 1449. If one of the n

1.	The H.C.F. of two numbers is 23 and their LCM is 1449. If one of the numbers is 161, find the other.
Answer» Step-by-step explanation: Given, HCF=23 LCM=1449 LET the two numbers be a and b. Let a=161. We have to find b. We know that HCF(a,b)×LCM(a,b)=a×b ⇒23×1449=161×b ⇒23× 161 1449 =b ⇒b=23×9 ∴b=207 Thus, the other NUMBER is 207.

The H.C.F. of two numbers is 23 and their LCM is 1449. If one of the numbers is 161, find the other.

Answer»

Step-by-step explanation:

Given, HCF=23

LCM=1449

LET the two numbers be a and b. Let a=161. We have to find b.

We know that

HCF(a,b)×LCM(a,b)=a×b

⇒23×1449=161×b

⇒23×

161

1449

⇒b=23×9

∴b=207

Thus, the other NUMBER is 207.