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The ground state energy of hydrogen atom is-13.6 eV. What are the kinetic and potential energies of the electron in this state ? |
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Answer» Total energy `=(1)/(2)mv^(2)+((-Kze^(2))/(r )) " "( because (mv^(2))/(r )=(Kze^(2))/(r^(2)))` `=(Kze^(2))/(2 r)` `= -13.6 eV` (for `n=1, z=1`) Kinetic energy `=(1)/(2) mv^(2)=(Kze^(2))/(2r)=13.6eV` Potential energy `=(-Kze^(2))/(r )=2xx13.6= -27.2 eV` |
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