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The greatest value of the function-5 sino + 12 cose(1) 12(2) 13(3) 7(4) 17 |
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Answer» Answer: Wait ẞruh Explanation: Answer: The maximum is 13 and minimum is − 13 . Explanation: f ( t ) = 5 sin t + 12 cos t . We can compound these TWO OSCILLATIONS into a single SINE oscillation. f ( t ) = 13 ( ( 5 13 ) sin t + ( 12 13 ) cos t )
= 13 ( cos b sin t + sin b cos t )
= 13 sin ( t + b ) , where sin b = 12 13 and cos b = 5 13 . So, − 13 ≤ f ( t ) = 13 sin ( t + b ) ≤ 13
The amplitude of the oscillation is 13 and the period is 2 π
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