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The greatest height to which a man can throw a stone is h. What will be the greatest distance upto which he can throw the stone? |
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Answer» SOLUTION :Maximum height: `H=(U^(2)sin^(2)THETA)/(g)impliesH_(max)=(u^(2))/(2G)=h(at""theta=90^(@))` Maximum range `R_(max)=(u^(2))/(g)=2H` |
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