1.

The greatest height to which a man can throw a stone is h. What will be the greatest distance upto which he can throw the stone?

Answer»

SOLUTION :Maximum height:
`H=(U^(2)sin^(2)THETA)/(g)impliesH_(max)=(u^(2))/(2G)=h(at""theta=90^(@))`
Maximum range `R_(max)=(u^(2))/(g)=2H`


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