1.

The greater and least resultant of two forces are 7 N and 3 N respectively. If each of the force is increased by 3 N and applied at 600600. The magnitude of the resultant is​

Answer»

ong>Answer:

Let , magnitude of the two FORCES be F

1

and F

2

.

Given,

for GR ether resultant θ=0

0

=

F

1

2

+F

2

2

+2F

1

F

2

cos0

=

(F

1

+F

2

)

2

=F

1

+F

2

=7N............(i)

Now,forleastresultantθ=180

0

=

F

1

2

+F

2

2

+2F

1

F

2

cos

180

=

(F

1

+F

2

)

2

A

=F

1

+F

2

=3N............(ii)

Adding equation (i) and (ii) we get,

2F

1

=10;F

1

=5N

Putting VALUE of F

1

in (i) we get,

F+2=2N

After adding 3N to each force we get,

F

1

′

=8N

F

2

′

=5N

When they are applied at θ=60

0

Resultant force F will be,

After solving we will get,

F=

129


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