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The gravitational potential energy of a rocket of mass 200kg at a height of 10^(7)m from the earth's surface is 10^(9)s. The potential energy of the rocket at a height of 26.4xx10^(6)m from the surface of earth is: |
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Answer» `-1.5xx10^(9)J` `(U')/(U)=((R+h)/(R+h'))` `=((6.4+10)xx10^(6))/((6.4+26.4)xx10^(6))` `=(16.4)/(32.8)=(1)/(2)` `thereforeU'=-(U)/(2)=(-10^9)/(2)=-0.5xx10^(9)J` |
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