1.

The gravitational potential energy of a rocket of mass 200kg at a height of 10^(7)m from the earth's surface is 10^(9)s. The potential energy of the rocket at a height of 26.4xx10^(6)m from the surface of earth is:

Answer»

`-1.5xx10^(9)J`
`-0.5xx10^(9)J`
`-2.5xx10^(9)J`
`-2XX10^(9)J`

SOLUTION :`U=-(GMm)/((R+h))""U'=-(GMm)/((R+h'))`
`(U')/(U)=((R+h)/(R+h'))`
`=((6.4+10)xx10^(6))/((6.4+26.4)xx10^(6))`
`=(16.4)/(32.8)=(1)/(2)`
`thereforeU'=-(U)/(2)=(-10^9)/(2)=-0.5xx10^(9)J`


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