1.

The gravitational potential energy of a body of mass m at the earth's surface is mgR_e . Its gravitational potential energy at a height R_efrom the earth's surface will be ..... (Here R_eis the radius of earth)

Answer»

`-2 mg R_e`
`2 mg R_e`
`1/2 mg R_e`
`-1/2 mg R_e`

Solution :`IMPLIES DeltaU = U_(2) - U_1 = (MGH)/(1+(H)/(R_e) ) = (mgh)/(1+R_e/R_e) = (mgR_e)/2`
`:. U_2 - (-mg R_e) = (mgR_e)/2`
`:. U_2 =-1/2 mg R_e`


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