The gravitational field due to a mass distribution is E=A/x^(2) in x-direction. Here A is a constant. Taking x the gravitational potential to be zero at infinity, potential at x is

The gravitational field due to a mass distribution is E=A/x^(2) in x-d

1.	The gravitational field due to a mass distribution is E=A/x^(2) in x-direction. Here A is a constant. Taking x the gravitational potential to be zero at infinity, potential at x is
Answer» `(2A)/X` `(2A)/x^(3)` `A/x` `A/(2x^(2))` Answer :C