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The graph shows variation of stopping potential `V_(0)` versus frequency of incident radiation `v` for two photosensitive metals `A` and `B`. Which of two metals has higher threshold frequency and why? |
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Answer» `K_(max)=hupsilon0-phi` `V=(hupsilon)/(e )-(varphi)/(h)` `varphi_(A) gt varphi_(B)` `upsilon_(A_0) gt upsilon_(B_(0))` |
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