1.

The graph shows variation of stopping potential `V_(0)` versus frequency of incident radiation `v` for two photosensitive metals `A` and `B`. Which of two metals has higher threshold frequency and why?

Answer» `K_(max)=hupsilon0-phi`
`V=(hupsilon)/(e )-(varphi)/(h)`
`varphi_(A) gt varphi_(B)`
`upsilon_(A_0) gt upsilon_(B_(0))`


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