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the graph displaythe load against plot from metal wire of diameter 1.5 mm and origonal length 1m.when the load reaches tje value of point A the wirebroke .Fromthe graph deduce value of force cpnstant and the young modulus dor the metal of the wire |
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Answer» Explanation:The APPLIED LOAD =F=mg=2×9.8=19.6N diameter =1mm=1×10 −3 m => radius=0.5×10 −7 m Area , A=3.14r 2 =3.14×0.25×10 −6 =0.785×10 −6 We know that, stress=Force/area =19.6/0.785×10 −6 24.96×10 −6 change in length,ΔL=1mm=10 −3 m Length,L=3m hencestrain=ΔL/L =10 −3 /3 we know that young's modulus is given by the RATIO of stress and strain, Hence, E=24.96×10 −6 /10 −3 /3 =74.8×10 9 =7.48×10 10 Nm −2 |
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