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The glasses of capacity 3 L, 5 L and 7 L contain mixture of milk and water with milk concentrations 60%, 50% and 20% respectively. The contents of three glasses are emptied into a large vessel. Find the ratio of milk to water in the resultant mixture.1). 52 : 492). 11 : 233). 127 : 634). 19 : 31 |
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Answer» In the 3L glass, Concentration of MILK = 60% ∴ Volume of milk = 60% of 3L = 3 × 60/100 = (9/5) = 1.8L---(1) ⇒ Concentration of water = 40% ∴ Volume of water = 40% of 3L = 3 × 40/100 = 6/5 = 1.2L---(2) Volume of milk = 50% of 5 = 2.5L---(3) Volume of water = 5L – 2.5L = 2.5L---(4) In the 7L glass, Volume of milk = 20% of 7L = (7/5) = 1.4 L---(5) Volume of water = 7 – (7/5) = (28/5) = 5.6L ---(6) ∴ From 1, 2, 3, 4, 5 and 6, In the TOTAL mix, Total volume of milk = 1.8 + 2.5 + 1.4 = 5.7L Total volume of water = 1.2 + 2.5 + 5.6 = 9.3L ∴ ratio of milk: water = 5.7: 9.3 = 19: 31 Thus, ratio of Milk : Water = 19 : 31. |
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