1.

The glasses of capacity 3 L, 5 L and 7 L contain mixture of milk and water with milk concentrations 60%, 50% and 20% respectively. The contents of three glasses are emptied into a large vessel. Find the ratio of milk to water in the resultant mixture.1). 52 : 492). 11 : 233). 127 : 634). 19 : 31

Answer»

In the 3L glass,

Concentration of MILK = 60%

∴ Volume of milk

= 60% of 3L

= 3 × 60/100

= (9/5) = 1.8L---(1)

⇒ Concentration of water = 40%

∴ Volume of water

= 40% of 3L

= 3 × 40/100

= 6/5 = 1.2L---(2)

SIMILARLY, in the 5L glass,

Volume of milk

= 50% of 5

= 2.5L---(3)

Volume of water

= 5L – 2.5L

= 2.5L---(4)

In the 7L glass,

Volume of milk

= 20% of 7L

= (7/5) = 1.4 L---(5)

Volume of water = 7 – (7/5) = (28/5) = 5.6L ---(6)

∴ From 1, 2, 3, 4, 5 and 6,

In the TOTAL mix,

Total volume of milk = 1.8 + 2.5 + 1.4 = 5.7L

Total volume of water = 1.2 + 2.5 + 5.6 = 9.3L

∴ ratio of milk: water = 5.7: 9.3 = 19: 31

Thus, ratio of Milk : Water = 19 : 31.


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