The given figure shows parallelogram ABCD.Points M and N lie in diagon

1.	The given figure shows parallelogram ABCD.Points M and N lie in diagonal BD such thatDM=BN. Prove that :(i) ΔDMC=ΔBNAand so CM=AN(ii) ΔAMD≅ ΔCNB and so AM=CN(iii) ANCM is a parallelogram.
Answer» $The given figure shows parallelogram ABCD. Points M and N lie in diagonal BD such that D M = B N .$ $Prove that : (i) Δ D M C = Δ B N A a n d s o C M = A N (i i) Δ A M D ≅ Δ C N B a n d s o A M = C N (i i i) ANCM is a parallelogram.$

The given figure shows parallelogram ABCD.Points M and N lie in diagonal BD such thatDM=BN. Prove that :(i) ΔDMC=ΔBNAand so CM=AN(ii) ΔAMD≅ ΔCNB and so AM=CN(iii) ANCM is a parallelogram.

Answer»

$The given figure shows parallelogram ABCD. Points M and N lie in diagonal BD such that D M = B N .$

$Prove that : (i) Δ D M C = Δ B N A a n d s o C M = A N (i i) Δ A M D ≅ Δ C N B a n d s o A M = C N (i i i) ANCM is a parallelogram.$