The given figure represents the phasor diagram of a series LCR circuit connected to an AC source. At instant t when the source voltage is given by V=V0cosωt, the current in the circuit in terms of peak current I0 will beGiven:VOR=√3 V = Voltage Across ResistorVOL=3 V = Voltage Across Inductor VOC=2 V = Voltage Across capacitor

The given figure represents the phasor diagram of a series LCR circuit

1.	The given figure represents the phasor diagram of a series LCR circuit connected to an AC source. At instant t when the source voltage is given by V=V0cosωt, the current in the circuit in terms of peak current I0 will beGiven:VOR=√3 V = Voltage Across ResistorVOL=3 V = Voltage Across Inductor VOC=2 V = Voltage Across capacitor
Answer» The given figure represents the phasor diagram of a series $L C R$ circuit connected to an $A C$ source. At instant $t$ when the source voltage is given by $V = V_{0} cos ω t$ , the current in the circuit in terms of peak current $I_{0}$ will be Given: $V_{O R} = \sqrt{3} V$ = Voltage Across Resistor $V_{O L} = 3 V$ = Voltage Across Inductor $V_{O C} = 2 V$ = Voltage Across capacitor

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