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The general solution of the differential equation `ydx+(x+2y^(2))dy=0` isA. `xy+y^(2)=c`B. `3xy+y^(2)=c`C. `xy+2y^(3)=c`D. `3xy+2y^(3)=c` |
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Answer» Correct Answer - D `ydx+(x+2y^(2))dy=0` `ydx+xdy+2y^(2)dy=0` `d(xy)+2y^(2)dy=0` Integrating both sides we get `impliesxy+(2y^(3))/(3)=` constant `implies3xy+2y^(3)=C` |
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