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The function f(x)=acosx + btanx + x had extreme values at X=0 and X=π/6, then1) a=-2/3, b=-12) a=2/3,b=-13) a=-2/3, b=14)a=2/3, b=1 |
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Answer» The function f(x)=acosx + btanx + x had extreme values at X=0 and X=π/6, then 1) a=-2/3, b=-1 2) a=2/3,b=-1 3) a=-2/3, b=1 4)a=2/3, b=1 |
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