The frequency of tuning fork is 500Hz and thevelocity of sound in air

1.	The frequency of tuning fork is 500Hz and thevelocity of sound in air 340ms 1. How far doessound travel when the fork executes50 vibrations?
Answer» Given:- • FREQUENCY of the tuning fork = 500 Hz • Velocity of sound in air = 340m/s • NUMBER of VIBRATIONS = 50 To find :- • DISTANCE travelled by the sound Solution:- We know that distance travelled by the wave in one vibration is it's wavelength (λ) . Thus distance covered by the wave when it executes 50 vibrations :- => d = 50×λ => d = 50λ ----(1) Now, we know that :- λ = υ/ν ----(2) Where :- • λ is the wavelength. • υ is the velocity of sound. • ν is the frequency. From, eq.1 and eq.2, we get :- => d = 50(υ/ν) => d = 50(340/500) => d = 50×0.68 => d = 34 m Thus, the sound travels a distance of 34m .

The frequency of tuning fork is 500Hz and thevelocity of sound in air 340ms 1. How far doessound travel when the fork executes50 vibrations?

Answer»

• FREQUENCY of the tuning fork = 500 Hz

• Velocity of sound in air = 340m/s

• DISTANCE travelled by the sound

We know that distance travelled by the wave in one vibration is it's

wavelength (λ) .

Thus distance covered by the wave when it executes 50 vibrations :-

=> d = 50×λ

=> d = 50λ ----(1)

Now, we know that :-

λ = υ/ν ----(2)

Where :-

• λ is the wavelength.

• υ is the velocity of sound.

• ν is the frequency.

From, eq.1 and eq.2, we get :-

=> d = 50(υ/ν)

=> d = 50(340/500)

=> d = 50×0.68

=> d = 34 m

Thus, the sound travels a distance

of 34m .