1.

The frequency of a particle performing SHM is 12 hz,. Its amplitude is 4 cm. Its initial displacement is 2 cm towards positive extreme positon. Its equation for displacement is

Answer»

`x=0.04 COS (24pi t +(PI)/6)`
`x=0.04sin(24pit)`
`x=o0.04sin(24pit+(pi)/6)`
`x=0.04cos (24pit)`

ANSWER :C


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