The freezing point depression of 0.001 m Kx[Fe(CN)6] is 7.44×10−3 K – InterviewSolution

1.	The freezing point depression of 0.001 m Kx[Fe(CN)6] is 7.44×10−3 K .Determine the value of x.Given:(Kf)water=1.86 K kg mol−1 Assume complete ionisation of Kx[Fe(CN)6]
Answer» The freezing point depression of $0.001 m K_{x} [F e (C N)_{6}]$ is $7.44 \times 10^{- 3} K$ . Determine the value of x. Given: $(K_{f})_{w a t e r} = 1.86 K k g m o l^{- 1}$ Assume complete ionisation of $K_{x} [F e (C N)_{6}]$

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