Saved Bookmarks
| 1. |
The fraction of the total volume occupied by the atoms present in a simple cube isA. `pi/4`B. `pi/6`C. `pi/sqrt(3sqrt2)`D. `pi/sqrt(4sqrt2)` |
|
Answer» Correct Answer - B In a simple cube, no. of atoms/unit cell =`8xx1/8=1` Volume of the atom =`4/3pir^3` Volume of the cube=`a^3=(2r)^3=8r^3 (because a=2r)` `therefore` Fraction occupied=`(4/3 pir^3)/(8r^3)=pi/6` |
|