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The fraction of the total volume occupied by the atoms present in a simple cube isA. `pi/4`B. `pi/6`C. `pi/sqrt(3sqrt2)`D. `pi/sqrt(4sqrt2)`

Answer» Correct Answer - B
In a simple cube, no. of atoms/unit cell =`8xx1/8=1`
Volume of the atom =`4/3pir^3`
Volume of the cube=`a^3=(2r)^3=8r^3 (because a=2r)`
`therefore` Fraction occupied=`(4/3 pir^3)/(8r^3)=pi/6`


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