The four resistors 20ohm,40ohm,20+x ohm,80ohm if the bridge is balance

1.	The four resistors 20ohm,40ohm,20+x ohm,80ohm if the bridge is balanced respectively form a Wheatstone bridge. Find the value of x
Answer» The value of x = 20 ohm. • According to the principle of wheatstone bridge, (Resistor r1) / (Resistor R2) = (Resistor r3) / (Resistor r4) • GIVEN , Value of Resistor r1 = 20 ohm Value of Resistor r2 = 40 ohm Value of Resistor r3 = (20+x) ohm Value of Resistor r4 = 80 ohm • Then by using PRINCIPAL of wheatstone bridge, (20 / 40) = [(20 + x)/80] ½ = [(20 + x)/80] 40 = 20 + x x = 20 ohm

The four resistors 20ohm,40ohm,20+x ohm,80ohm if the bridge is balanced respectively form a Wheatstone bridge. Find the value of x

Answer»

The value of x = 20 ohm.

• According to the principle of wheatstone bridge,

(Resistor r1) / (Resistor R2) = (Resistor r3) / (Resistor r4)

• GIVEN ,

Value of Resistor r1 = 20 ohm

Value of Resistor r2 = 40 ohm

Value of Resistor r3 = (20+x) ohm

Value of Resistor r4 = 80 ohm

• Then by using PRINCIPAL of wheatstone bridge,

(20 / 40) = [(20 + x)/80]

½ = [(20 + x)/80]

40 = 20 + x

x = 20 ohm

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The four resistors 20ohm,40ohm,20+x ohm,80ohm if the bridge is balanced respectively form a Wheatstone bridge. Find the value of x

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