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The force of attractions between two charges `8muC` and `-4muC` is 0.2 N. Find the distance of separation.A. 1.2 mB. 12 mC. 120 mD. 0.12 m |
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Answer» Correct Answer - A Given, that, F=0.2 N, `Q_(1) = 8muC`, `Q_(2)=4muC` `therefore` Force between two charges, F=`K(Q_(1)Q_(2))/r^(2))` or 0.2 = `9 xx 10^(9) xx (8 xx 10^(-6) xx 4 xx 10^(-6))/0.2` or r=12cm |
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