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The force F needed to keep the block at equilibrium in given figure is (pulley and string aremassless)(1)Mg/5(2)Mg/4(3)Mg/2(4)Mg/3 |
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Answer» 1) Let the TENSION in the STRING be 'T' . Since, net force along the string is 0. => F-T=0 => F=T 2) Now, Tension is constant along the string . => Tension on both SIDES of pulley is 'T'. We need, to find the VALUE of 'F' to KEEP the system in equilibrium . => Net force on pulley must be 0. => 2T-Mg = 0 => T = mg/2. Hence, the value of F=T=Mg/2. |
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