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The following statement Demorgan’s theorem of Boolean algebra. Identify and state ‘Break the line, change the sign’. |
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Answer» Demorgan’s theorems, Demorgan’s first theorem, \(\overline{x+y}\) = \(\bar x .\bar y\) Demorgan’s second theorem, \(\overline{x-y} = \bar x + \bar y\) |
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