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The focus of the parabola `y^(2)-x-2y+2=0` isA. `(1//4,0)`B. `(1//2)`C. `(3//4,1)`D. `(5//4, 1)` |
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Answer» Correct Answer - D We have, `y^(2)-2y=x-2rArr(y-1)^(2)=x-1` The coordinates of the focus ot this parabola are given by `x-1=1/4,y-1=0" "[because" "y^(2)=4ax" has focus at (a, 0)"]` `rArr" "x=5//4, y=1` Hence, the coordinates of the focus are (5/4, 1). |
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