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The focal length of lens of refractive index 2.5 in air is 30 cm. If it is immersed in a liquid of refractive index 53 , then its focal length will be |
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Answer» ONG>ANSWER: For the lens in air fa1=(aμg−1)[R11−R21] ⇒151=(1.5−1)[R11−R21] ⇒152=R11−R21 When the lens is immersed in water fw1=(aμwaμg−1)[R11−R21] ⇒fw use this FORMULA and solve question |
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