1.

The focal length of lens of refractive index 2.5 in air is 30 cm. If it is immersed in a liquid of refractive index 53 , then its focal length will be​

Answer» ONG>ANSWER:

For the lens in air

fa1=(aμg−1)[R11−R21]

⇒151=(1.5−1)[R11−R21]

⇒152=R11−R21

When the lens is immersed in water

fw1=(aμwaμg−1)[R11−R21]

⇒fw

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