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The focal length of a lens is - 50 cm. Calculate its Power. What is the nature of the lens |
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Answer» ong>ANSWER: given : F = -50cm or +50×10^-2m
so find p =?
formula p =1/f
p = 1/-50×10^-2
p= 100/-50
P =- 2
so your final answer is -2 as the POWER is negative its concave lens and nature of concave lens is virtual image,erect and diminished. hope it helps! plz mark me as BRAINLIEST! |
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