1.

The focal length of a lens is - 50 cm. Calculate its Power. What is the nature of the lens

Answer»

ong>ANSWER:

given : F = -50cm or +50×10^-2m

so find p =?

formula p =1/f

p = 1/-50×10^-2

p= 100/-50

P =- 2

so your final answer is -2

as the POWER is negative its concave lens

and nature of concave lens is virtual image,erect and diminished.

hope it helps!

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