1.

The flux linked with a circuit is given by `phi=t^(3)+3t-7` . The graph between time (`x`-axis) and induced emf (`y`-axis) will beA. straight line through the originB. straight line with positive interceptC. straight line with negative interceptD. parabola not through the origin

Answer» Correct Answer - D
`phi=t3+3t-7`
`e=-(dphi)/"dt"=-(3t^2 +3)`
e v/s graph : y = – 3x2 – 3, this is parabola, not through origin.


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