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The flux linked with a circuit is given by `phi=t^(3)+3t-7` . The graph between time (`x`-axis) and induced emf (`y`-axis) will beA. straight line through the originB. straight line with positive interceptC. straight line with negative interceptD. parabola not through the origin |
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Answer» Correct Answer - D `phi=t3+3t-7` `e=-(dphi)/"dt"=-(3t^2 +3)` e v/s graph : y = – 3x2 – 3, this is parabola, not through origin. |
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