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The first term ofan A.P. of consecutive integer is p'+1. The sum of(2p+ 1) terms of this seriesexpressed ascan be |
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Answer» first term,a=p^2 +1and n=2p+1d=2 (given is the series of consecutive integers)and S=(n/2)(2a+(n-1)d)S=((2p+1)/2)(2 (p^2 +1)+((2p+1)-1)×2)S=((2p+1)/2)(2p^2 +2 +4p)S=((2p+1)/2)(2(p^2 +2p+1))S=(2p+1)(p^2 +2p +1)S=(2p+1)(p+1)^2 |
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