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The first term of an AP is 5, the last term is 45 and the sum is 400. Find the number of terms and the common difference? |
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Answer» Solution: Sn = 400 = n/2 (5+45) ➪ n = 400/25 = 16 Now, a16 = 45 = 5 + d x 15 ➪ 15d = 40 d = 8/3 |
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