1.

The first term of an AP is 5, the last term is 45 and the sum is 400. Find the number of terms and the common difference?

Answer»

Solution: S = 400 = n/2 (5+45)

➪​ n = 400/25 = 16

Now, a16 = 45 = 5 + d x 15

➪ ​15d = 40

d = 8/3



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