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The first order rate constant for the decomposition of ethyliodide by the Reaction of C2H51-âC2H4 + HI at 600k is1.60 x 10- sec. Its energy of activation is 209 kj/m.Calculate rate constant of the reaction at 700k. |
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Answer» Ea= 209 kJ mol-1 = 209 x 103J mol-1T₁ = 600 K, k₁= 1.6x10-5s-1T₂= 700 K, k₂ = ?R = 8.314 JK-1 mol-1log(K₂/K₁) = Ea/2.303R [ (T₂-T₁)/T₁T₂] =209x 103/2.303 x 8.314 x [700 – 600)/ 600 x 700] =2.5989(K₂/K₁) = antilog 2.5989 = 397.1K₂ = 397.1 x K₁= 397.1 x 1.6x10-5s-1K₂ =6.35 x 10-3s-1 |
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