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The first and second term of five consecutive numbers are 16 and 64 respectively. The fifth term will be? |
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Answer» a1 = 16 = 42 = (4 x 1)2 a2 = 64 = 82 = (4 x 2)2 ∴ an = (4n)2 ∴ a5 = (4 x 5)2 a1 = 16 = 42 = (4 x 1)2 a2 = 64 = 82 = (4 x 2)2 ∴ an = (4n)2 ∴ a5 = (4 x 5)2 = 202 = 400 |
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