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The figure shows part of certain circuit, find, a. power dissipted in `5Omega` resistance, b.Potential difference `V_C-V_B` c.Which battery is being charged? |
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Answer» Correct Answer - A::B::C a. Current flowing through resistance `5Omega` is `11 A` power dissipted `=i^2R` `=(121)5=605W` `b. V_B+8V+3V=12V-12V-5V=V_C` `V_B+11V-5V=V_C` `6V=V_C-V_B` c. both batteries are being charged. |
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