1.

The figure shows elliptical orbit of a planet 'M' about the Sun 'S', the shaded area SCD is twice the shaded area SAB. If t_(1) is the time for the planet to move from C and D and t_(2) is the time to move from A to B then.

Answer»

Solution :ACCORDINGTO Kepler.slaw
LAWOF areas
`(DeltaA)/(Deltat) ` = constant
`DeltaA prop Deltat`
`(DeltaA_(SCD))/(DeltaA_(SAB)) = (t_(1))/(t_(2))`
`(2A)/A = (t_(1))/(t_(2))`
` :. "" t_(1) = 2t_(2)`


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