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The figure shows electronic wave function for a hydrogen atom. A. The quantum number of this state is 6B. The wavelength of this electron is `6pir_(0)` (r_(0) is radius of ground state)C. It can go to ground state by emitting 3 different photonsD. On deexcitation it emits at least one line in infra red region of spectrum. |
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Answer» Correct Answer - B::C (A) `n=3` (B) `2pir=nlambda Rightarrow 2pi3^(2)r_(0)=nlambda Rightarrow lambda=6pir_(0)` (C) No `=^(3)C_(2)=3` (D) all lines in Balmer or lyman series. |
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