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The fifth term of the ap is 19and is first term is 3 what will be it's common different |
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Answer»
Let a and d are first term and common DIFFERENCE of an A . P. nth term = tn = a + ( n - 1 )d----------( 1 ) i) Given t 5 = 19 a + 4d = 19 -------(2) ii ) differnce of the eighth term from the thirteeth term = 20 t 13 - t 8 = 20 a + 12d - ( a + 7d ) = 20 a + 12d - a - 7d = 20 5D = 20 d = 20/ 5 d = 5 Put d = 5 in ( 2 ) a + 4d = 19 a + 4 × 5 = 19 a + 20 = 19 a = 19 - 20 a = - 1 Therefore, a = -1 , d = 5 Required A .P is a , a+ d , a + 2D , a + 3d , ..... -1 , 4 , 9 , 14, 19 , .... I HOPE this will useful to you. |
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