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The factorisation of am2+ bm2+ bn2+ an2is |
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Answer» (m²+n²)(a+b) Step-by-step EXPLANATION: am²+bm²+bn²+an² "TAKING out m² COMMON from both am²and bm² and n² from bn²and an²" m²(a+b) +n²(a+b) m²+n²(a+b) |
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