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The external diameter of a 5 metre long hollow tube is 10 cm and the thickness of its wall is 5 mm. If the specific resistance of copper be `1.7xx10^(5)` ohm-metre, then determine its resistance.A. `5.7xx10^(-5)Omega`B. `2.7xx10^(-5)Omega`C. `2xx10^(-5)Omega`D. `5xx10^( -5)Omega` |
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Answer» Correct Answer - A Area of cross section of tube, `A= pi (r_(2)^(2)-r_(1)^(2))` `=3.14[(0.05)^(2)-(0.045)^(2)]` `=14.91xx10^(-4)m^(2)` Thus, `R=(rho l)/(A)=(1.7xx10^(-8)xx5)/(14.91xx10^(-4))=5.7xx10^(-5)Omega` |
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