The exterior angles of a triangle are 3y, 4y, 5y. find the smallest in

1.	The exterior angles of a triangle are 3y, 4y, 5y. find the smallest interior angle of the triangle.
Answer» ong>Answer: 3y Step-by-step explanation: EXTERIOR angle = 180 - interior angle 3y = 180 - a a = 180 - 3y 4y=180-b b=180-4y 5y=180-c c=180-5y In TRIANGLE SUM of angles = 180 a +b+c = 180 180-3y+180-4y+180-5y=180 1803-12y=180 1802=12y 1802÷12=y 30=y 3y=330=90 4y=430=120 5y=530=150 Hence, 3y is the SMALLEST interior angle of the triangle.

The exterior angles of a triangle are 3y, 4y, 5y. find the smallest interior angle of the triangle.

Answer»

ong>Answer:

Step-by-step explanation:

EXTERIOR angle = 180 - interior angle

3y = 180 - a

a = 180 - 3y

4y=180-b

b=180-4y

5y=180-c

c=180-5y

In TRIANGLE SUM of angles = 180

a +b+c = 180

180-3y+180-4y+180-5y=180

180*3-12y=180

180*2=12y

180*2÷12=y

30=y

3y=3*30=90

4y=4*30=120

5y=5*30=150

Hence, 3y is the SMALLEST interior angle of the triangle.