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The expression tan−1(6x−8x31−12x2)−tan−1(4x1−4x2) in the interval |2x|<1√3 simlifies to: |
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Answer» The expression tan−1(6x−8x31−12x2)−tan−1(4x1−4x2) in the interval |2x|<1√3 simlifies to: |
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