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The expression (125 - x) = (5 - x) (x2 + ax + b). Find the value of a |
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Answer» (125-x) = (5-x) (x^2+AX+b) = 5x^2+5AX+5b-x^3-ax^2-bx = -x^3-5ax^2+5ax+5b-b (125-x) = -x^3-5ax-bx+5b = -x^3-5ax-bx+5b+x = -x^2-5ax-bx+5b = -x^2-5ax-bx+5b-125 5ax = -x^2-bx+5b-125 ax = -x^2-bx+5b-125/5 a = -x^2/x-bx+5b-25 = -x-bx+5b-25 --- 1 -×1 --- a = x+bx-5b+25 Finally, the VALUE of a is x+bx-5b+25 |
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