Saved Bookmarks
| 1. |
The exclude value of the rational expression x3 + 8 by x2 - 2x - 8 is |
|
Answer» \(\frac{x^3+8}{x^2-2x-8}=(x+2)(x^2-2x-8)+\frac{12x+2x}{(x-2x-8)}\) \(=(x+2)(x+2)(x-4)+\frac{12(x+2)}{(x+2)(x-4)}\) \(=(x+2)(x-4)\) \(=(x+2)^2(x-4)+\frac{12}{x-4}\) |
|