1.

The exclude value of the rational expression x3 + 8 by x2 - 2x - 8 is

Answer»

\(\frac{x^3+8}{x^2-2x-8}=(x+2)(x^2-2x-8)+\frac{12x+2x}{(x-2x-8)}\)

\(=(x+2)(x+2)(x-4)+\frac{12(x+2)}{(x+2)(x-4)}\)

\(=(x+2)(x-4)\)

\(=(x+2)^2(x-4)+\frac{12}{x-4}\)



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