1.

The equlibrium constant K, for the reaction N2+3H2⇌2NH3 is 1.64×104atm at 400∘C . What will be the equilibrium constant at 500∘C, if heat of reaction in this temperature range is - 105185.8 Joules.

Answer»

The equlibrium constant K, for the reaction N2+3H22NH3 is 1.64×104atm at 400C . What will be the equilibrium constant at 500C, if heat of reaction in this temperature range is - 105185.8 Joules.




Discussion

No Comment Found