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the equivalent resistance of 200 resistors each of 100 ohms connected in parallel is found to be p by 2 ohm. find the value of p |
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Answer» AnswerCorrect option ISA(66.7 ± 1.8) ΩHere, R 1 (100±3)Ω;R 2 =(200±4)Ω The equivalent resistance in parallel combination isR 1 1 = R 1 1 + R 2 1 , R p 1 = 1001 + 2001 = 2003 ,R p = 3200 =66.7ΩThe error in equivalent resistance is GIVEN byR p2 ΔR p = R 12 ΔR 1 + R 22 ΔR 2 ;ΔR p =ΔR 1 ( R 1 R p ) 2 +ΔR 2 ( R 2 R p ) 2 =3( 10066.7 ) 2 +4( 20066.7 ) 2 =1.8Ω Hence, the equivalent resistance along with error in parallel combination is (66.7 ± 1.8)Ω. |
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