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The equivalent inductance of two inductances is `2.4` henry when connected in parallel and `10` henry when connected in series. The difference between the two inductance isA. `2` henryB. `3` henryC. `4` henryD. `5` henry |
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Answer» Correct Answer - A `L_(s)=L_(1)+L_(2)=10H` …..(i) `L_(p)=(L_(1)L_(2))/(L_(1)+L_(2))=2.4H` ……(ii) On solving (i) and(ii)`L_(1)L_(2)=24` Also `(L_(1)-L_(2))^(2)=(L_(1)+L_(2))^(2)-4L_(1)L_(2)` `implies(L_(1)-L_(2))^(2)=(10)^(2)-4xx24=4impliesL_(1)-L_(2)=2H` |
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