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The equivalent inductance of two inductances is `2.4` henry when connected in parallel and `10` henry when connected in series. The difference between the two inductance isA. 8 H, 2HB. 6H, 4HC. 5H, 5HD. 7H, 3H |
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Answer» Correct Answer - B In series connection `L_(1)+L_(2)=10 H " ".....(ii)` and in parallel connection `(L_(1)L_(2))/((L_(1)+L_(2)))=2.4H" "...(ii)` Subsitituting the vlaue of `(L_(1)+L_(2))` form (i) into, (ii), we get `L_(1)L_(2)=(2.4)(L_(1)+L_(2))=2.4xx10=24` `(L_(1)L_(2))=(L_(1)+L_(2))^(2)-4L_(1)L_(2)` `L_(1)-L_(2)=[(10)^(2)-4xx24]^(1//2)=2H" "...(iii)` Solvin (i) and (iii), we get `L_(1)=6H,L_(2)=4H` |
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