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The equivalent inductance of two inductances is `2.4` henry when connected in parallel and `10` henry when connected in series. The difference between the two inductance isA. 5HB. 4HC. 3HD. 2H |
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Answer» Correct Answer - D Given `L_(P)=2.4 H, L_(S)=10H` Let `L_(1) and L_(2)` be the two inductance. We use the laws of series and parallel resistances for `L_(1)` and `L_(2)`. then `L_(1)+L_(2)=10 and 1/(L_1)+1/(L_2)=1/2.4` `:. 2.4 = (L_(1)L_(2))/(L_(1)+L_(2)) :. 2.4 = (L_(1)L_(2))/(10)` `:. L_(1)L_(2)= 24` But `L_(1)-L_(2) = sqrt((L_(1)+L_(2))^(2)-4L_(1)L_(2))` `sqrt(100-4 xx 24)` `sqrt(100-96) = 24` `L_(1)-L_(2) = 2H`. |
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